A quadratic equation is shown:x2 - 14x + 41 = 0
Which of the following is the first correct step to write the above equation in the form (x - p)2 = 9, where p and q are integers?
x2 - 14x + 41 + 8 = 0 + 8
x2 - 14x + 41 + 9 = 0 + 9
x2 - 14x + 41 - 8 = 0 - 8
x2 – 14x + 41 - 9 = 0 - 9

Answers

Answer 1
Answer:

Answer:

The correct answer is the first option

Step-by-step explanation:

Quadratic Equation

The standard form of a quadratic equation is

ax^2+bx+c=0

Sometimes we need to change the expression of the same equation to the form

(x-p)^2=q

To accomplish that change, we usually modify the left-hand expression to make it look like the square of a binomial.

The given quadratic equation is

x^2-14x+41=0

Recall the square of a binomial is

(x-p)^2=x^2-2px+p^2

The first term is already present. The second term gives us the value of p:

-2px=-14x

Solving

p=7

Now we need to produce the third term p^2=49. We only have 41, thus we need to add 8 to both sides of the equation:

x^2-14x+41+8=0+8

The correct answer is the first option


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Answers

Answer:

3

Step-by-step explanation:no

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Answers

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Will mark as brainliest if correct! (#14)

Answers

Answer:

B and D

Step-by-step explanation:

To find the percentage, you divide Martin's correct answers by the total number of questions, then multiply the result by 100.

To find the fraction, it's correct answers/total questions.

Answer:

you should get your answer to be ,B and D

Solve the algebraic expression n + 8, if n = 15

Answers

you mean evaluate

n+8
if n=15
15+8=
10+5+8=
10+3+2+8=
13+10=
23
plug in 15 so n+8 ...15+8=23

Dilate the figure by the scale factor. Then enterthe new coordinates.
(1.4) B
A (-3,1)
K = 3
A'([?],[])
B’([],[)
C'([],D))
C (2,-3)
Enter (Photo)​

Answers

Answer:

there you go but im not sure . hope its helpful and good luck ;)

What is the domain?
(-∞,∞)

[0,∞)

(-∞,0]

-2, 2

Answers

Answer:

(-∞,∞)

Step-by-step explanation:

The domainisthepossiblex values,sofor this functionx^2,the possiblex valuesare all thevalues

(-infinity ,infinity)